A 5-in. object to be radiographed at a 44-in. SID lies 6 in. from the IR. What will be the image width?

To determine the image width when radiographing an object, it's essential to understand the concepts of magnification and the relationship between the object size, distance from the image receptor (IR), and source-to-image distance (SID).

In this scenario, the object size is 5 inches, the SID is 44 inches, and the object is positioned 6 inches from the IR. The total distance from the x-ray source (or tube) to the object needs to be calculated first. Since the object is 6 inches from the IR and the SID is 44 inches, the distance from the source to the object (SOD) can be determined as follows:

SOD = SID - object-to-IR distance

SOD = 44 in. - 6 in. = 38 in.

Now, to find the magnification, we can use the magnification formula:

Magnification = SID / SOD

Magnification = 44 in. / 38 in. = 1.1579 (approximately)

Next, we apply the magnification to the actual size of the object:

Image width = Object size x Magnification

Image width = 5 in. x 1.1579 ≈ 5.79