If an object of 3 inches is placed 4 inches from the image recorder and the SID is 36 inches, what will be the image width?

To determine the image width when an object is placed at a specific distance from the image recorder with a given source-to-image distance (SID), we can utilize the magnification formula. Magnification is defined as the ratio of the image size to the object size and can be calculated using both the distance to the object and the distance to the image.

The formula to calculate magnification is:

[ \text{Magnification} (M) = \frac{\text{Image Size}}{\text{Object Size}} = \frac{\text{SID}}{\text{SOD}} ]

Where:

• SID is the source-to-image distance (36 inches).

• SOD is the source-to-object distance, which can be calculated as the SID minus the distance of the object from the image recorder (4 inches from the recorder indicates it is 36 inches - 4 inches = 32 inches from the source).

Using the formula:

1. First, find the SOD: ( SOD = 36 , \text{inches} - 4 , \text{inches} = 32 , \text{inches} ).

2. Calculate the magnification:

[ M = \frac{